Difference between revisions of "161-A5.1"
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== Expected Output == | == Expected Output == | ||
+ | |||
+ | {| class="wikitable" | ||
+ | |- | ||
+ | | | ||
+ | | <math>n = 2</math> | ||
+ | | <math>n = 4</math> | ||
+ | | <math>n = 16</math> | ||
+ | | <math>n = 256</math> | ||
+ | | <math>n = 65536</math> | ||
+ | |- | ||
+ | | <math>\epsilon = 0.1</math> | ||
+ | | 1 | ||
+ | | 1 | ||
+ | | 4 | ||
+ | | 39 | ||
+ | | 7291 | ||
+ | |- | ||
+ | | <math>\epsilon = 0.3</math> | ||
+ | | 1 | ||
+ | | 1 | ||
+ | | 6 | ||
+ | | 86 | ||
+ | | 20158 | ||
+ | |- | ||
+ | | <math>\epsilon = 0.8</math> | ||
+ | | 1 | ||
+ | | 3 | ||
+ | | 11 | ||
+ | | 193 | ||
+ | | 51758 | ||
+ | |- | ||
+ | |} |
Revision as of 04:30, 8 May 2021
In this module, you have learned that it is possible to synthesize extremal channels from multiple copies of a given binary-input channel. In particular, the binary erasure channel (BEC) has the property that all synthesized channels are equivalent to BECs.
Task Description
Your task in Module 5 is simple: given the erasure probability of a BEC, you are to count the number of synthetic channels with erasure probability that is better (lower) than the original BEC.
You need to write a function count_bad_channels
which will take two arguments:
blocklength
- anint
that is a power of two, denoting the blocklength or, equivalently, the number of synthetic channels produced via the polar transform.erasure_prob
- afloat
, a positive real number between 0 and 1, indicating the erasure probability of the original BEC.
The function must return an int
corresponding to the number of synthetic BECs with erasure probabilities strictly less than erasure_prob
.
Expected Output
1 | 1 | 4 | 39 | 7291 | |
1 | 1 | 6 | 86 | 20158 | |
1 | 3 | 11 | 193 | 51758 |